Question 621746
You live near a bridge that goes over a river. The underneath side of the bridge is an arch that can be modeled with the function y = -0.000495x^2 + 0.619x where x and y are in feet. How high above the river is the bridge (the top of the arch)?
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The vertex is on the line x = -b/2a
x = -0.619/(-0.00099) = 61900/99
Sub that for x in the equation

--> y =~ 193.516 ft max
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How long is the section of bridge above the arch?
Find the 2 zeroes of the eqn.  The straight line distance is the difference between the 2 zeroes.
*[invoke solve_quadratic_equation -.000495,.619,0]
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One solution is 0, so the distance = 1250.5 feet