Question 57367
(1/x)-(1/x+1)
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1/x+1
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Rewrite as:
[x+1-x]/[x(x+1)]/[1/(x+1)]
Invert the denominator and multiply to get:
[1/x(x+1)]*[(x+1)/1]
Cancel the (x+1) factor to get:
1/x
Cheers,
Stan H.