Question 621761
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Hi,
Two cards are drawn <U>without replacement</U> from a standard deck of cards
P(both diamonds) = {{{(13/52)(12/52)}}}
P(2nd club, given 1st is club) = 12/51
P(A|B) = P(A and B)/P(B) = {{{(13/52)(12/51)/(13/52)}}}
P(2nd is a 9, given 1st was a 3) = 4/51
P(A|B) = P(A and B)/P(B) = {{{(4/52)(4/51)/(4/52)}}}