Question 57359
The rules we're going to use are:
{{{highlight((a^m)^n=a^(mn))}}}
{{{highlight((ab)^m=a^mb^m)}}}
{{{highlight(a^(-m)=1/a^m)}}}
simplify this expression. dealing with exponents
{{{(2^(5/3)y^(-2/3))^3}}}
{{{2^((5/3)*3)y^((-2/3)*3)}}}
{{{2^(15/3)y^(-6/3)}}}
{{{2^5y^-2}}}
{{{2^5/y^2}}}  
{{{2*2*2*2*2/y^2}}}
{{{32/y^2}}}
Happy Calculating!!!