Question 621403
find x if log3 x-4 + log3 x-2 =1
.
{{{log(3,x-4) + log(3,x-2) =1}}}
{{{log(3,(x-4)(x-2)) =1}}}
{{{(x-4)(x-2) = 3^1}}}
{{{x^2-6x+8 = 3}}}
{{{x^2-6x+5 = 0}}}
{{{(x-1)(x-5) = 0}}}
x = {1,5}
we can throw out the 1 (extraneous) leaving:
x = 5