Question 621340
Given a quadratic equation with rational coefficients with a root of 5-i: 
a)What is another root to the equation? 
complex conjugate of 5-i is the other root:
5+i
b) What are the factors of the equation? 
s1 = 5-i
s2 = 5+i
(x - (5-i)) and (x - (5+i))
(x-5+i) and (x-5-i)
.
c) What is the quadratic equation with the given root?
b/a = -(s1+s2)
b/a = -(5-i+5+i)
b/a = -(5+5)
b/a = -10
.
c/a = s1s2
c/a = (5-i)(5+i)
c/a = 25-i^2
c/a = 25-(-1)
c/a = 25+1
c/a = 26
.
x^2 + (-10)x + 26
x^2-10x+26