Question 621303
3< 4 + 3x/2< 2
-1<+ 3x/2< -2
-2<+ 3x< -4
-2/3<x<-4/3
x<-4/3
x>-2/3
Solution:
In set notation
{x|x<-4/3, x>-2/3}
number line:
<====-4/3)..........(-2/3====>
In interval notation
solution: (-&#8734;,-4/3) U (-2/3<&#8734;)