Question 621269
I am assuming that A. P. stands for arithmetic progression (or arithmetic sequence).
The three numbers are m-d, m, and m+d (m is the middle number and d is the common difference in the arithmetic progression).
The difference between the first and the last is
{{{(m+d)-(m-d)=2d=8}}} --> {{{highlight(d=4)}}}
The product of the first and the last numbers is
{{{(m+d)*(m-d)=m^2-d^2=m^2-4^2=m^2-16=20}}}
{{{m^2-16=20}}} --> {{{m^2=16+20}}} --> {{{m^2=36}}} --> {{{highlight(m=6)}}}
So the numbers would be 6-4, 6, 6+4 or 2, 6, 10.
But if the numbers are allowed to be negative, we could have {{{highlight(m=-6)}}} and the numbers could be
-6-4, -6, -6+4 or -10, -6, -2.