Question 621310
{{{27^((x+1)) = 9^((2x-4))}}}
note that 27 = 3^3 and 9 = 3^2, so we can rewrite this to
{{{3^(3(x+1)) = 3^(2(2x-4))}}}
If the bases are equal, the exponents are equal, so we have
3(x+1) = 2(2x-4)
:
3x + 3 = 4x - 8
3 + 8 = 4x - 3x
11 = x
;
:
Check this on your calc, (replace x with 11)
27^12 = 1.5(10^17)
9^18 = 1/5(10.17)