Question 621180
Find the equation for the line that passes through the point (3,5), and that is parallel to the line with the equation (y-1=-2/3(x-1). 
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Note: a fraction (a/b) can be considered as "a divided by b".
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Slope of:
y-1=-2/3(x-1)
is -2/3
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A line parallel will have the same slope.
So, now we have:
m (slope) is -2/3
and one point (3,5)
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Plug into "point-slope" form:
y - y1 = m(x -x1)
y - 5 = (-2/3)(x - 3)
y - 5 = (-2/3)x - (-2/3)3
y - 5 = (-2/3)x - (-2)
y - 5 = (-2/3)x + 2
y = (-2/3)x + 7  (this is what they're looking for in "slope-intercept" form)