Question 621179
The first thing is: how much of a head start does
the 1st plane get?
{{{ d[1] = 590*1 }}}
{{{ d[1] = 590 }}} mi
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Let {{{ d }}} = distance the 2nd plane has to travel
until the 1st plane passes it.
{{{ 1800 - d }}} is the distance the 1st plane travels
until it passes the 2nd plane
Let {{{t}}} = the time from when the 2nd plane
takes off until they meet
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Equation for 1st plane
(1) {{{ 1800 - d - 590 = 590t }}}
Equation for 2nd plane
(2) {{{ d = 660t }}}
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Substitute (2) into (1)
(1) {{{ 1800 - 660t - 590 = 590t }}}
(1) {{{ 1250t = 1210 }}}
(1) {{{ t = .968 }}} hrs
And, the times from when the 1st plane takes off
until they meet is {{{ 1 + .97 }}}
1.97 hours