Question 621158
<pre>
Solve for &#952; in the equation tan &#952; = 2.42 when 180° < &#952; < 360°.

180° < &#952; < 360° consists of quadrants III and
IV. 

<pre>
Observing tan &#952; = 2.42, noticing that 2.47 is a positive number and
realizing that the tangent is only positive in quadrant III, we know that
&#952; is an angle in quadrant III, so 
180° < &#952; < 270°

So we use the inverse tangent feature to get 67.54845354°.  But that is NOT 
the answer because 67.54845354° is an angle in quadrant I, not quadrant III.
The value 67.54845354° tells how many degrees &#952; swings into quadrant III.

{{{drawing(200,200,-1,1,-1,1, graph(200,200,-1,1,-1,1), line(-2,0,2,0),line(0,2,0,-1),      line(0,0,cos(247*pi/180),sin(247*pi/180)),
  red(arc(0,0,1.5,-1.5,0,247)),
green(arc(0,0,1.2,-1.2,180,247)) )}}}

So we must add 67.54845354° + 180° and get 247.5484535°.

In the drawing above, the green arc represents the 67.54845354°, which
is the reference angle, and the red arc represents the 247.5484535°. 

Edwin</pre>