Question 621126
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Hi,
y=x^2+2x+4   Note:  (0,4)is where Parabola crosses the y axis
y = (x+1)^2 -1 + 4
{{{y = 1*(x+1)^2 +3}}}   V(-1,3) Yes!  Important 1st Step
For graphing:
2nd step: Which direction does the Parabola Open? 
 y = a(x-h)^2 + k   is the general form of a parabola opening Up or Down, a = 1 > 0, parabola opens Up
3rd Step:  what is the Line of symmetry:  x = -1
Plotting Vertex and y-intercept and putting in the line of symmetry,
 allows us to determine the graph
{{{drawing(300,300,   -6, 6, -6, 6,  blue(line(-1,6,-1,-6))  , grid(1),
circle(-1, 3,0.3),
circle(0, 4,0.3),
graph( 300, 300, -6, 6, -6, 6,0,x^2+2x+4))}}}