Question 57324
Hi CH,
{{{(-9-sqrt(108))/3}}}
108=36*3 and 36 is a perfect square, 6*6=36
{{{(-9-sqrt(36)*sqrt(3))/3}}}
{{{(-9-6*sqrt(3))/3}}}  Factor out a 3 from the numerator.
{{{3(-3-2*sqrt(3))/3}}} Cancel the 3's
{{{cross(3)(-3-2sqrt(3))/cross(3)}}}
{{{highlight(-3-2sqrt(3))}}}
Happy Calculating, CH!!!