<PRE><B>Question 621021</B>
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There are 9 ways to pick the first batter, then for each of those 9 ways there are 8 ways to pick the second for a total of 72, then for each of those 72 ways to pick the first two, there are 7 ways to pick the third...and so on.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 9\ \times\ 8\ \times\ 7\ \times\ 6]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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