Question 620925
First, I would add 3 to both sides of the equal sign to get a more convenient, equivalent equation:
{{{1=-3+abs(2-(1/4)y)}}} --> {{{1+3=-3+3+abs(2-(1/4)y)}}} --> {{{4=abs(2-(1/4)y)}}}
Then I would split the problem into two cases (two equations) and I would solve each equation, getting a total of two solutions.
If {{{2-(1/4)y>=0}}}, the equation is {{{2-(1/4)y=4}}}
If {{{2-(1/4)y<0}}}, the equation is {{{-(2-(1/4)y)=4}}} or (multiplying both sides of the equal sign times (-1) ),
{{{2-(1/4)y=-4}}}
To solve {{{2-(1/4)y=4}}}, I would first subtract 2 from both sides.
Then I would multiply both sides times (-4).
{{{2-(1/4)y=4}}} -->{{{2-2-(1/4)y=4-2}}} --> {{{-(1/4)y=2}}} --> {{{-4*(-1/4)y)=(-4)*2}}} --> {{{y=-8}}}
I would solve {{{2-(1/4)y=4}}} the same way
{{{2-(1/4)y=-4}}} -->{{{2-2-(1/4)y=-4-2}}} --> {{{-(1/4)y=-6}}} --> {{{-4*(-1/4)y)=(-4)*(-6)}}} --> {{{y=24}}}