Question 620956
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 9\ <\ 4(-5)\ -\ x\ +\ 3\ +\ 2x]


Collect terms in the RHS


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 9\ <\ -17\ +\ x]


Add *[tex \LARGE -x\ -\ 9] to both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ <\ -26]


Multiply both sides by *[tex \LARGE \frac{1}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ <\ -13]


Plug something smaller than *[tex \LARGE -13] back into the original inequality in place of *[tex \LARGE x], then do the arithmetic to see if you have a true statement.  Do it again with *[tex \LARGE x\ =\ -13], and see if you have a false statement.  Hint: *[tex \LARGE -12] is NOT smaller than *[tex \LARGE -13], *[tex \LARGE -14] is.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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