Question 620921
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Let *[tex \LARGE d] be the distance between the two towns.  At 50 mph, the time to travel *[tex \LARGE d] miles is *[tex \LARGE \frac{d}{50}], at 60 mph, the time to travel *[tex \LARGE d] miles is *[tex \LARGE \frac{d}{60}], and at 55 mph, the time to travel *[tex \LARGE 2d] miles (remember, round trip at 55), is *[tex \LARGE \frac{2d}{55}]


The times differ by a half hour with the sum of the differing speeds taking longer, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{d}{50}\ +\ \frac{d}{60}\ -\ \frac{1}{2}\ =\ \frac{2d}{55}]


Solve for *[tex \LARGE d]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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