Question 620909
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If they are going to meet in 4 hours, then the sum of their speeds must be *[tex \LARGE \frac{444}{4}\ =\ 111] miles per hour.


Since their speeds differ by 15 mph, we can say one is going *[tex \LARGE x] mph and the other is going *[tex \LARGE x\ +\ 15] mph, so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ x\ +\ 15\ =\ 111]


Solve for *[tex \LARGE x], then calculate *[tex \LARGE x\ +\ 15]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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