Question 620642
So let us call the first number 'n'. We know that the second number is n+47 or n-47

So the first number, n = 2(n + 47)-31 or 2(n - 47)-31

solve for n when n is smaller than the second number (i.e. second number is equal to n+47):

n = 2(n+47)-31
n = 2n+94-31
n-2n=94-31
-n=63
n=-63

and the second number is n+47 = -16

when n is the larger number and therefore the second number is smaller (n-47):

n = 2(n-47)-31
n = 2n-94-31
n-2n = -125
-n = -125
n=125

and the second number is n-47 = 78

If the question definitely means that the first number is the smaller one then you would just use the n+47 and end up with the two negative numbers -63 and -16

If it does not imply then you would have to give both solutions but I actually expect that the first scenario is expected.