Question 620670
={{{(2x^3/y^-4)^-3}}}
={{{((2x^3)(y^4))^-3}}}
={{{(2x^3y^4)^-3}}}
={{{1/(2x^3y^4)^3}}}
={{{1/2^3x^9y^12}}}
={{{1/8x^9y^12}}}