Question 620678
{{{x^2-x=56}}}


{{{x^2-x-56=0}}}


Now use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(-1)+-sqrt((-1)^2-4(1)(-56)))/(2(1))}}}


{{{x = (1+-sqrt(1-(-224)))/(2)}}}


{{{x = (1+-sqrt(225))/2}}}


{{{x = (1+sqrt(225))/2}}} or {{{x = (1-sqrt(225))/2}}}


{{{x = (1+15)/2}}} or {{{x = (1-15)/2}}}


{{{x = 16/2}}} or {{{x = -14/2}}}


{{{x = 8}}} or {{{x = -7}}}


So the solutions are {{{x = 8}}} or {{{x = -7}}}