Question 620590
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The function is in vertex form, so read the coordinates of the vertex directly and plot that.  Coincidentally, the vertex is on the x-axis in this case, so you have your x-intercept also.  If you don't know how to interpret the vertex form, Google "vertex form of a parabola" and pick the first thing that comes up.


Then substitute 0 for x and calculate the y-coordinate of the y-intercept.  Plot that.


Figure out how far along the x-axis it is from the origin to the vertex, then go that same distance on the other side of the vertex to find a point with the same y-value as the y-intercept (symmetry)


Pick any other x-value (different from 0, the x-coordinate of the vertex, and the x-coordinate of the point symmetrical to the y-intercept) and calculate the value of the function for that x-value.  Then use symmetry again to find a symmetrical point on the other side of the vertex.


That gives you 5 points which should be enough.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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