<PRE><B>Question 620242</B>
elson wants to use a few pieces of silver to make a bracelet.
 Some of the jewelry is 70% silver, and the rest is 58% silver.
 Nelson needs 26.00g of 65% silver. How much of each alloy should he use?
;
Let x = amt of 70% silver
the total amt is to be 26 gr, therefore:
(26-x) amt of 58% silver
:
A typical mixture equation
:
.70x + .58(26-x) = .65(26)
.70x + 15.08 - .58x = 16.9
.70x - .58x = 16.9 - 15.08
.12x = 1.82
x = 1.82/.12
x = 15{{{1/6}}} gr of 70% silver
and
26 - 15{{{1/6}}} = 10{{{5/6}}} gr of 58% silver</PRE>