Question 620565
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-5,4\right)]. So this means that {{{x[1]=-5}}} and {{{y[1]=4}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(15,-4\right)].  So this means that {{{x[2]=15}}} and {{{y[2]=-4}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-4-4)/(15--5)}}} Plug in {{{y[2]=-4}}}, {{{y[1]=4}}}, {{{x[2]=15}}}, and {{{x[1]=-5}}}



{{{m=(-8)/(15--5)}}} Subtract {{{4}}} from {{{-4}}} to get {{{-8}}}



{{{m=(-8)/(20)}}} Subtract {{{-5}}} from {{{15}}} to get {{{20}}}



{{{m=-2/5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-5,4\right)] and *[Tex \LARGE \left(15,-4\right)] is {{{m=-2/5}}}