Question 620522
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Hi,
The manager of a grocery store wishes to look at the efficiency of his staff.
 He takes a random sample of 44 customers. The average length of time it took
 for a customer out was 164.62 minutes with a standard deviation of 34.79 minutes
Calculate a 90% confidence interval for the true average checkout time in his market?
    ME = 1.645(34.79/6.633) 
  164.62 - ME < {{{mu}}} < 164.62 + ME