Question 620436
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Hi
Using the standard slope-intercept form for an equation of a line y = mx + b 
 where m is the slope and b the y-intercept.  
line perpendicular to y =  1/3x + 5 through (2, 1)
Note: slopes of perpendicular lines  are negative reciprocals of one another
New Line:
 y = -3x + b   ||using Pt(2,1) to solve for b
 1 = -6 + b
 7 = b
 y = -3x + 7
{{{drawing(300,300,   -6, 6, -6, 8, grid(1),
circle(2, 1,0.2),

graph( 300, 300, -6, 6, -6, 8,0, -3x+7, (1/3)x+5))}}}