Question 57309
We'll use P to be the price of one pear and A to be the price of one apple:

First Equation: 6*P + 3*A = 3.90
Second Equation 2*P + 5*A = 3.30

Solve first eq. for P:
6P=3.90-3A
P=3.90/6 - 3A/6

Plug into second equation:
2*(3.90/6 - 3A/6) +5A = 3.30

Simplify:
1.3 - 6A/6 + 5A = 3.30
1.3 -A + 5A = 3.30
1.3 + 4A = 3.30
4A = 3.30-1.30
4A = 2
A = 0.5

So each apple (A) is $0.50

Plug into Eq 1 to find P:  6*P + 3*(.5)=3.90

6P + 1.5 = 3.90
6P =3.90-1.5
6P = 2.4
P = $.40

*[invoke linear "p", "a", 6, 3, 3.9, 2, 5, 3.3]