Question 620030
Log(9+9x)-log(11-x) = 2
We can combine the logs, - means divide
{{{log(((9+9x)/(11-x)))}}} = 2
Find the antilog of both sides [{{{10^x}}}]
{{{(9+9x)/(11-x)}}} = 100
multiply both sides by (11-x)
9 + 9x = 100(11-x)
9 + 9x = 1100 - 100x
9x + 100x = 1100 - 9
109x = 1091
x = {{{1091/109}}}
x = 10.009