Question 57288
{{{sqrt(b+3)=sqrt(2b-8)}}}  Square both sides.
{{{(sqrt(b+3))^2=(sqrt(2b-8))^2}}}
{{{b+3=2b-8}}}
{{{-b+b+3=-b+2b-8}}}
{{{3=b-8}}}
{{{8+3=b-8+8}}}
{{{11=b}}}
:
Check by substituting b=11 into the original equation, because even if you did everything right, you could get an extraneous solution.
{{{sqrt(11+3)=sqrt(2(11)-8)}}}
{{{sqrt(14)=sqrt(22-8)}}}
{{{sqrt(14)=sqrt(14)}}}  The solution is fine.
Happy Calculating!!!