Question 620186
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The degree of the numerator polynomial in f is less than the degree of the denominator polynomial, so the function is asymptotic to the *[tex \LARGE x]-axis.  Write an equation of the *[tex \LARGE x]-axis.


The function has a vertical asymptote with equation *[tex \LARGE x\ =\ a_i] for every real value *[tex \LARGE a] such that the denominator is equal to zero if *[tex \LARGE x\ =\ a_i].  Set the denominator equal to zero, then solve for all possible real roots, *[tex \LARGE a_i], then there will be a vertical asymptote at every vertical line *[tex \LARGE x\ =\ a_i].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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