Question 620118
Let the 3 consecutive odd integers = 
{{{ n }}}, {{{ n+2 }}}, and {{{ n + 4 }}}
{{{ 2*( n+ 4 - 6 ) = n + 2*( n + 2 ) - 23 }}}
{{{ 2*( n - 2 ) = n + 2n + 4 - 23 }}}
{{{ 2n - 4 = 3n - 19 }}}
{{{ n = 19 - 4 }}}
{{{ n = 15 }}}
{{{ n + 2 = 17 }}}
{{{ n + 4 = 19 }}}
The integers are 15, 17, and 19
check:
{{{ 2*( n+ 4 - 6 ) = n + 2*( n + 2 ) - 23 }}}
{{{ 2*( 19 - 6 ) = 15 + 2*( 17 ) - 23 }}}
{{{ 2*13 = 15 + 34 - 23 }}}
{{{ 26 = 49 - 23 }}}
{{{ 26 = 26 }}}
OK