Question 620085
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Hi,
Solve the system of equations by using the inverse of the coefficient matrix.
 -x-2y=8
 3x+4y=24 
{{{M = (matrix(2,2,a1,b1,a2,b2)) = a1b2-b1a2}}}                                  
{{{I = (1/(a1b2 - b1a2))(matrix(2,2,b2,-b1,-a2,a1))}}}

{{{M =( matrix(2,2,-1,-2,3,4))}}} = 2
{{{I = (1/2)(matrix(2,2,4,2,-3,-1))= (matrix(2,2,2,1,-1.5,-.5)) }}}
{{{(matrix(2,1,x,y))= (matrix(2,2,2,1,-1.5,-.5))(matrix(2,1,8,24))= (matrix(2,1,40,-24)) }}}