Question 619766
Hi, there--
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The point-slope formula for a linear equation is a good way to solve this:
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{{{(y-y[1])=m(x-x[1])}}}
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In this formula m is the slope of the line, and (x[1],y[1]} are the coordinates of a point on the line. In your problem, the slope m is -2/3 and the coordinates of the point are (5,0). Now we write the equation out using the point-slope form, substituting the values we know.
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{{{y-0=(-2/3)(x-5)}}}
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Simplify.
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{{{y=(-2/3)x+(10/3)}}}
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Any of these is an equation for the line you are interested in. You can also multiply every term by 3 to remove the fractions.
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{{{3y=-2x+10}}}
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Hope this helps. Feel free to email me if you questions about my response,
Ms.Figgy
math.in.the.vortex@gmail.com

Find the equation of the line that passes through (5,0) and has a slope of -2/3