Question 619820
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Hi,
The length of a rectangle is <u>5 cm less than twice the width</u> {{{highlight(x)}}} . 
Express as an integer the maximum width of the rectangle when the perimeter is less than 60 cm. 
 P = 2W + 2L = 2x + 2(2x-5)< 80
               2x + 2(2x-5)< 80
               6x < 90
                x < 15
CHECKING our Answer*** trying x = 14
2· 14 + 2(28-5) =  28 + 46 =  74 < 80