Question 619815
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Hi
What is the hypotenuse of a right angled triangle with the shortest sides being 4 and 6 to 2 d.p.?
Using the Pythagorean Theorem:
 c^2 = a^2 + b^2   || where c is the hypotenuse
 c = {{{sqrt(16 + 36) = sqrt( 52) = 7.21}}} to 2 d.p.