Question 619685
Hi, there--
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Solve for r.
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{{{0.3(2r-3)=0.2r+0.9}}}
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First, distribute 0.3 across the parentheses.
{{{0.6r-0.9=0.2r+0.9}}}
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Now we will rewrite this equation as a series of equivalent equations until we have isolated the variable r.
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Combine like terms. Let's combine the variables on the left side of the equation. Subtract 0.2r from both sides.
{{{0.6r-0.2r-0.9=0.2r-0.2r+0.9}}}
{{{0.4r-0.9=0.9}}}
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Combine the constant terms on the right side of the equation. Add 0.9 to both sides of the equation.
{{{0.4r-0.9+0.9=0.9+0.9}}}
{{{0.4r=1.8}}}
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We want to know the value of 1r so we divide both sides of the equation by the coefficient of r; that is 0.4.
{{{(0.4r)/0.4=1.8/0.4
{{{r=4.5}}}
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We can check our work by substituting 4.5 for r in the original equation.
{{{0.3(2r-3)=0.2r+0.9}}}
{{{0.3(2(4.5-3))=0.2(4.5)+0.9}}}
{{{0.3(9-3)=0.9+0.9}}}
{{{0.3(6)=1.8}}}
{{{1.8=1.8}}}
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This result shows that r=1.8 is the solution.
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Hope this helps. Feel free to email if you have questions about this solution,
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Ms.Figgy
math.in.the.vortex@gmail.com