Question 619671
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Hi,Re TY..sry misunderstood Your inquiry... Good work!
 *[tex \large\ \ log_x(log_5(x+5)) = 0]
             x^0 =  *[tex \large\ \ log_5(x+5)]
 *[tex \large\ \ log_5(x+5) =1]
  {{{5^1 = (x+5)}}}
     5 = x+5
      0 = x