Question 619542
If 4260 lbs of ore can produce 28 lbs of a pure metal,how much ore is required to produce 35 lbs of pure metal?
:
We can use a ratio equation
Let x = amt of ore to produce 35 lb
:
{{{x/4260}}} = {{{35/28}}}
cross multiply
28x = 4260 * 35
28x = 149100
x = {{{149100/28}}}
x = 5325 lb of ore required to produce 35 lb of metal