Question 57256
Boat is traveling from A to B at 33mph
Plane is also traveling from same A to B at 605mph.
Plane takes 104 hours LESS to make the trip.
How far apart are A and B.
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It does say they both went from A to B, therefore they are traveling the same distance. If we find the times required to make the trips, it's an easy calculation to find the distance
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Let t = boat's time to make the trip
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Then (t-104) = plane's time to make the trip
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Boat's speed is given as 33 mph;
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Plane's speed = 605 mph
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Dist = speed * time
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Plane's dist = Boat's dist
605(t-104) = 33t
605t - 62920 = 33t
605t - 33t = +62920
572t = 62920
   t = 62920/572
   t = 110 hrs for the boat to make the trip
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Remember that Dist = speed * time: 
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Dist = 33 * 110 = 3630 mi
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We can check out solution by finding the dist the plane travels, it should be the same.
605 *(110-104) =
605 * 6 = 3630 mi also from a to b
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How's that, did it make sense to you?