Question 619407
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Hi,
*[tex \large\ \ log_3(x+2) + log_3(10-x) = log_3(x+2)(10-x) = 3 ]
  3^3 = (x+2)(10-x) = 10x + 20 - x^2 - 2x
 27 = -x^2 + 8x + 20
   0 = -x^2 + 8x -7
   0 = x^2 - 8x + 7
      (x-7)(x-1) = 0 
        x = 7,1