<PRE><B>Question 619378</B>
Given three consecutive odd numbers such that the square of the second number is 104 less than the square of the third number. Find those numbers.
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1st: 2x-3
2nd: 2x-1
3rd: 2x+1
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Equation:
(2x-1)^2 = (2x+1)^2 -104
4x^2-4x+1 = 4x^2+4x+1 - 104
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8x = 104
x = 13
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1st: 2x-3 = 23
2nd: 25
3rd: 27
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Cheers,
Stan H.
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