Question 619296
If 11 coins are tossed what is the probability of getting EXACTLY 2 heads?
Use P(x=k)=nCk*p^k*q^(n-k)
Where p=probability of success and q=1-p, probability of failure


So
P(x=2)=(11C2)(1/2)^2(1/2)^(11-2)
=(11C2)(1/4)(1/512)
=(11C2)(1/2048)
=0.0269