Question 619265
To solve this problem, set it equal to 0.


2bc+4b-5c-10=0


Now factor the problem.  After trial and error, we come up with:


(2b-5)(c+2)=0


Now set each parentheses equal to zero to solve for b and c.


2b-5=0                 
  +5 +5                 
2b=5                   
b=5/2


c+2=0
c=-2



To check the solution, substitute the b and c values into the original problem and set equal to zero.