Question 619188
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Hi,
The height of a triangle is 6 m more than twice the length of the base{{{highlight(x)}}}.
The area of the triangle is 28 m^2 = L*H
  x(2x+6) =28
  2x^2 + 6x -28 = 0
   x^2 + 3x -14 = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
 {{{x = (-3 +- sqrt( 65))/(2) }}}  = (-3 +8.06)/2 = 2.5 rounded to 1 decimal point (throwing out neg solution for unit measure
length = 2.5m, height is 11m