Question 619099
find the remaining trig functions if sec(beta)=6/5 and tan(beta)<0
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sec>0 in quadrants I and IV
tan<0 in quadrants II and IV
So reference angle is in quadrant IV
sec=6/5=hypotenuse/adjacent side
By the pythagorean theorem: opposite side=&#8730;(6^2-5^2)=&#8730;(36-25)=&#8730;11
Trig functions as follows:
sec(beta)=6/5
cos(beta)=5/6
csc(beta)=-6/&#8730;11
sin(beta)=-&#8730;11/6
tan(beta)=-&#8730;11/5
cot(beta)=-5/&#8730;11