Question 618909
{{{5/2(x+1)}}},{{{1/2x}}},{{{3/2(x+1)^2}}}
Factor each denominator
{{{5/2(x+1)}}},{{{1/2x}}},{{{3/2(x+1)(x+1)}}}
Prime factors are {{{2}}},{{{x}}},{{{(x+1)}}}. 
{{{(x+1)}}} to the highest power is {{{(x+1)^2}}}
LCD = {{{2x(x+1)^2}}}