Question 618773
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Hi, Re TY, note: ALL info was put in terms of *[tex \large\ water]& each side of EQ has a total of 1 Liter of solution
how much *[tex \large\ water] (0% acid){{{highlight(x)}}} and how much stock solution (99%) of HCL*[tex \large\ 1% water]
must he mix to get 1 liter 5% HCL solution*[tex \large\ 95% water]
     Water = water
{{{ x + .01(1L-x) = .95*1L}}} 
      .99x = .94L
         x = .94L/.99 =.95L of water needs to be added
CHECKING our Answer***
   .95L + .01*.05 = .95L