Question 618712
Hi, there--
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You will need to use exponent rules to solve this problem. When you multiply two exponential expressions you add the exponents.
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We need to deal with the coefficients and variables separately. Let's start with the coefficients, -6 and 2. When we multiply these together we get -12. This gives us,
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{{{(-6x^3)(2x^5)=-12*(x^3)(x^5)}}}
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Now we multiply the variables. "x-cubed" times "x to the fifth power" is "x to the eighth power" since 3+5 is 8. So, 
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{{{-12*(x^3)(x^5)=-12x^8}}}
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You might be wondering how this "add the exponents when you multiply" rule works. Check this out...
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{{{x^3=x*x*x}}}
{{{x^5=x*x*x*x*x}}}
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When we multiply them together, we have eight factors of x, so
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{{{(x^3)(x^5)=x*x*x*x*x*x*x*x=x^8}}}
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Hope that helps. Feel free to email me at math.in.the.vortex@gmail.com if you have any questions about this.
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Ms.Figgy