Question 618708
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Hi,
<img src="http://upload.wikimedia.org/wikipedia/commons/thumb/d/da/PerimeterRectangle.svg/200px-PerimeterRectangle.svg.png">
the perimeter of a rectangleis 600 yards. What are the dimensions of the rectangle if the length is 50 yards more than the width{{{highlight(x)}}} ?
P = 2L + 2W = 2(x+50) + 2x = 600
          2(x+50) + 2x = 600
              4x = 500
               x = 125yd, the width.  the length is 175yd     (125yd + 50yd)